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If a home measures 28 x 52 ft. with a 28 x 12 ft. garage, what is the total livable area?

  1. 1,120 sq. ft.

  2. 1,040 sq. ft.

  3. 1,200 sq. ft.

  4. 1,000 sq. ft.

The correct answer is: 1,120 sq. ft.

To calculate the total livable area of the home, the correct approach involves determining the square footage of the main structure while excluding any non-livable spaces, such as the garage. First, calculate the area of the house: The dimensions are 28 feet by 52 feet. Thus, the area of the house is: 28 ft x 52 ft = 1,456 square feet. Next, we need to calculate the area of the garage: The dimensions of the garage are 28 feet by 12 feet, resulting in: 28 ft x 12 ft = 336 square feet. To find the total livable area, subtract the garage's area from the total area of the house: 1,456 sq. ft. (house) - 336 sq. ft. (garage) = 1,120 sq. ft. The resulting area of 1,120 square feet represents the total livable area of the home, which aligns with the first choice given in the question. Understanding that livable area calculations typically exclude garages, basements, and similar spaces is key to solving such problems accurately.